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{
Here's a solution in Borland Pascal 7.0 to your sorting problem. However, it
does one things slightly different from what you might expect: It uses
ASCIIbetical order, ie. spaces come before letters.
I hope you can adapt the program to your needs (your specific compiler etc).
The program uses Strings, but you can substitute them with Array [1..255] of
Char (of course, the displaying part should be changed). If you need the new
indices, try moving the P array out of the DoSort procedure.
Hope this helps.
Andy Kurnia
-----Sample output for input: THIS IS AN EXAMPLE ARRAY OF BYTES-----
-----SORTING.PAS, 1,742 bytes, Borland Pascal 7.0-----
{$A+,B-,D-,E-,F-,G+,I-,L-,N-,O-,P-,Q-,R-,S-,T-,V+,X+,Y-}
{$M 4096,0,0}
Program Sorting;
Var
S : String;
Function GetRow(X : Byte) : String;
Var
T : String;
Begin
If S[0] = ^@ Then Begin { Zero-length string check }
GetRow := '';
Exit
End
Else If X = 0 Then { Row 0 check }
X := Length(S);
T := S;
Delete(T, 1, (X - 1) Mod Length(S));
T := T + S;
T[0] := S[0]; { Cut unnecessary extra characters }
GetRow := T
End;
Var
A1, A2, A3, A4 : String; { Strings are Array Of Char }
Procedure DoSort;
Var
I, J : Byte;
P : Array[1..255] Of Byte; { Pointers to sorted position }
Begin
A1 := S;
A2 := S[Length(S)] + Copy(S, 1, Length(S) - 1);
For I := 1 To 255 Do
P[I] := I;
For I := 1 To Length(S) - 1 Do { The good old bubble sort }
For J := I + 1 To Length(S) Do
If GetRow(P[I]) > GetRow(P[J]) Then Begin
P[I] := P[I] Xor P[J]; { Exchange P[I] with P[J] }
P[J] := P[I] Xor P[J];
P[I] := P[I] Xor P[J]
End;
A3[0] := S[0]; { Copy just the length bytes }
A4[0] := S[0];
For I := 1 To Length(S) Do Begin { Lay the results out }
A3[I] := A1[P[I]];
A4[I] := A2[P[I]]
End
End;
Var
I : Byte;
Begin
Write('Enter test string: ');
ReadLn(S);
WriteLn('The matrix of strings:');
For I := 1 To Length(S) Do
WriteLn(GetRow(I));
DoSort;
WriteLn('[A1] = ', A1);
WriteLn('[A2] = ', A2);
WriteLn('[A3] = ', A3);
WriteLn('[A4] = ', A4)
End.
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