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(* ÚÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄ¿
³ Programated by Vladimir Zahoransky ³
³ Vladko software ³
³ Contact : zahoran@cezap.ii.fmph.uniba.sk ³
³ Program tema : Squards in squard - norekusion ³
ÀÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÄÙ *)
{
This is very popular effekt to present rekusion. This version
(how in all programs) is no rekusion version. This program is typycal
sort of rekusions. To undestatnd a rekusion is not diffycult, but to
undestand to no rekusion version. The rekusion is easy (writed with
one trick - rekpic20.pas), but for no rekusion version stay a big
difficult problem. For N=1 it is bigest squard. For N=2 it is :
ÚÄÄÄÂÄÄÄÂÄÄÄ¿ And here is a problem. In N=1 it is ONE squard,
³ ³ ³ ³ but in N=2 are there 4 small squards, for N=3 ... .
ÃÄÄÄÙ ÀÄÄÄ´ This problem is not difficult, if you change this
³ ³ problem for Ostack. (Object stack for turtle graphic)
ÃÄÄÄ¿ ÚÄÄÄ´ It is very easy for all who undestand Ostack. (statical
³ ³ ³ ³ and dynamical) We work with v - rekusive variable,
ÀÄÄÄÁÄÄÄÁÄÄÄÙ N - level of rekusion and a (s) - it is direction.
This program (for easy version) is good to work in parts.
Part1 : vhere is primitive part (nathing)
and penetrate part
Part2-4 : emerge of rekusion
First work : Init stack. (The stack is empty) If we do something then
push or pop from stack. If we penetrare (for smallest squard) then
push if emerge then pop. We give to stack v=1 (we are penetrating)
with input parameters. Then is a cykle. Finish work if is stack
empty. (work is finished) If we work one course of cycle then we
pop one data from stack. One case item muth push somedata!
Well, it is good and what make case ?
1 : there is penetration - decrementation of n to level 1 in
momental situation. If you are N squard level (exm. 3) and
you want to finish this level you muth to draw x-mal squard
effekt N-1. This part draw lines to level 1. push(2,n,a);
2..4 : make increment of v. It finish level from minimalized N from
part 1. If v<4 then push(v+1,n,a); This command make v for end
of N for this squardpart.
Situation is: We are in N=3 (for example we have level of
rekusion n=5) Part1 draw situation for 1 squard - (to smallest
squard) and 2..4 finish all levels from 1 to momental N. (n=3)
Then begin momental n=4. And work part 1 then 2..4. If we are
in momental level Nm=N-1 then one don't work because it is
finished.
Well, it is full documentation. If you want other information,
please see rekusion version (rekpic20.pas) or make krokuj:=true
then you will step program in graphic mode.
}
uses oKor, oStack_b;
type MyKor=object(Kor)
Procedure Squard(n:integer; a:real);
End;
procedure MyKor.Squard(n:integer; a:real);
var v:integer;
s:Stack;
begin
with s do
begin
init;
push(1,n,a);
while not empty do
begin
pop(v,n,a);
case v of
1: if n=0 then
else
begin
Dopredu(a); Vlavo(90);
push(2,n,a);
push(1,n-1,2*a/5);
end;
2,3,4: begin
Dopredu(a); Vlavo(90);
if v<4 then push(v+1,n,a);
push(1,n-1,2*a/5);
end;
end {case}
end {while}
end {with}
end;
var k:MyKor;
begin
with k do
begin
Init(200,-200,0);
Squard(6,400);
PresunXY(-300,230); Pis('Squards level 6 - Norekusion');
CakajKlaves;
Koniec;
End
End.
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